[GAP Forum] Table of Marks

[tendai shumba]

Dear forum,
I have done the following calculation on a machine running GAP version 4.7.7 as well as on machines running older versions 
of the program:gap>to:=TableOfMarks("M11");
TableOfMarks( "M11" )gap> RepresentativeTom(to,19);
Group([ (3,9)(4,7)(5,12)(10,11), (3,12)(4,5)(6,11)(7,9), (3,5)(4,6)(9,10)
(11,12) ]).
My question is that since we know that the Mathiue group M_11 is a permutation group of degree11, would it not mean that all the subgroups are of degree 11? If the answer to my question is in the affirmative 
then there is something wrong with the representative of the conjugacy class of groups given above since the cycle (3,9)(4,7)(5,12)(10,11) because the third transposition (5,12) has a 12.
Can someone explain? Assistance offered will be greatly appreciated.
 Regards,
Tendai