[GAP Forum] Groups of order 192

[Derek Holt]

Dear  Hadi, Dear GAP Forum,

Since 192 = 3 X 2^6, for any divisor d of 192, either d or 192/d is a
power of 2, so G has a subgroup of order d or of order 192/d by Sylow's
Theorem.

Best regards,
Derek.

On Thu, Sep 11, 2014 at 09:52:39PM +0430, hadi Hooshmand wrote:
> Dear All,
> 
> Let $G$ be a group of order 192 and $d$ a positive divisor of it . Is it
> true
> that there exists a subgroup of $G$ with order or index $d$?
> 
> Is there any GAP code to check the question by an ordinary computer?
> Does anyone know the answer?
> 
> Thanks in advance
> _______________________________________________
> Forum mailing list
> Forum at mail.gap-system.org
> http://mail.gap-system.org/mailman/listinfo/forum